(3x-1)(x^2-4)=0

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Solution for (3x-1)(x^2-4)=0 equation:


Simplifying
(3x + -1)(x2 + -4) = 0

Reorder the terms:
(-1 + 3x)(x2 + -4) = 0

Reorder the terms:
(-1 + 3x)(-4 + x2) = 0

Multiply (-1 + 3x) * (-4 + x2)
(-1(-4 + x2) + 3x * (-4 + x2)) = 0
((-4 * -1 + x2 * -1) + 3x * (-4 + x2)) = 0
((4 + -1x2) + 3x * (-4 + x2)) = 0
(4 + -1x2 + (-4 * 3x + x2 * 3x)) = 0
(4 + -1x2 + (-12x + 3x3)) = 0

Reorder the terms:
(4 + -12x + -1x2 + 3x3) = 0
(4 + -12x + -1x2 + 3x3) = 0

Solving
4 + -12x + -1x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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